Class 11 Maths Notes — All 14 Chapters (CBSE 2026-27)
All 14 chapters
CBSE Class 11 Maths syllabus and marks at a glance
The current CBSE curriculum for Class 11 Mathematics has 14 chapters spread across 5 units. The theory paper is for 80 marks and the internal assessment adds 20 marks, for a total of 100. CBSE does not publish official chapter-wise marks, but it does publish unit-wise weightage, which is what the table below shows.
| Unit | Theory marks | Chapters |
|---|---|---|
| Sets and Functions | 23 marks | Sets, Relations and Functions, Trigonometric Functions |
| Algebra | 25 marks | Complex Numbers and Quadratic Equations, Linear Inequalities, Permutations and Combinations, Binomial Theorem, Sequences and Series |
| Coordinate Geometry | 12 marks | Straight Lines, Conic Sections, Introduction to Three Dimensional Geometry |
| Calculus | 8 marks | Limits and Derivatives |
| Statistics and Probability | 12 marks | Statistics, Probability |
| Total | 80 | 14 chapters |
Source: CBSE Mathematics curriculum for 2026-27 (cbseacademic.nic.in). Weightages can change; always check the official PDF for your session.
Sets
Sets and Functions · 23 marksThe language the rest of Class 11 is written in. Get the notation right and later chapters become much easier to read.
Concepts you must be able to explain
- A set is a well-defined collection. Roster form lists the elements; set-builder form states the rule they satisfy.
- The empty set has no elements; a singleton has one. Equal sets contain exactly the same elements, whatever the order.
- A is a subset of B if every element of A is in B. The number of subsets of a set with n elements is 2ⁿ.
- Union, intersection, difference and complement obey De Morgan’s laws, which are best remembered with Venn diagrams.
- n(A ∪ B) = n(A) + n(B) − n(A ∩ B) counts without double-counting; extend it carefully to three sets.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Subsets | 2ⁿ subsets, 2ⁿ − 1 proper subsets | n is the number of elements. |
| Union count | n(A ∪ B) = n(A) + n(B) − n(A ∩ B) | Subtract the overlap once. |
| Three sets | n(A ∪ B ∪ C) = Σn(A) − Σn(A ∩ B) + n(A ∩ B ∩ C) | Inclusion–exclusion. |
| Difference | n(A − B) = n(A) − n(A ∩ B) | Elements in A but not in B. |
| De Morgan | (A ∪ B)′ = A′ ∩ B′; (A ∩ B)′ = A′ ∪ B′ | Complement flips the operation. |
Common mistakes
- Writing {∅} for the empty set instead of ∅.
- Forgetting that the empty set is a subset of every set.
- Using n(A ∪ B) = n(A) + n(B) when the sets overlap.
- Confusing ‘proper subset’ with ‘subset’ in counting questions.
Exam tip: Draw a Venn diagram before substituting numbers. Nearly every sets word problem becomes a matter of filling in regions.
Relations and Functions
Sets and Functions · 23 marksDomain, range and the definition of a function. Precise answers matter more than long ones.
Concepts you must be able to explain
- The Cartesian product A × B is the set of all ordered pairs (a, b). If A has m elements and B has n, then A × B has mn elements.
- A relation from A to B is any subset of A × B; a function is a relation in which every element of the domain has exactly one image.
- Domain is the set of allowed inputs, co-domain is the target set, and range is the set of values actually produced.
- For a real function, exclude values that make a denominator zero or put a negative number under an even root.
- Standard functions — identity, constant, polynomial, modulus, greatest integer, reciprocal — should be recognised from their graphs.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Cartesian product size | n(A × B) = n(A) × n(B) | Ordered pairs, so (a, b) ≠ (b, a). |
| Number of relations | 2^(mn) relations from A to B | Every subset of A × B is a relation. |
| Domain of a quotient | Denominator ≠ 0 | Exclude those x values. |
| Domain of a square root | Radicand ≥ 0 | For even roots. |
| Modulus | |x| = x if x ≥ 0; −x if x < 0 | Range is [0, ∞). |
Common mistakes
- Calling any relation a function — a single input with two outputs is not a function.
- Writing the range as the co-domain.
- Forgetting to exclude the value that makes a denominator zero.
- Treating (1, 2) and (2, 1) as the same ordered pair.
Exam tip: State domain and range in interval notation. It is shorter, unambiguous and exactly what the marking scheme expects.
Trigonometric Functions
Sets and Functions · 23 marksThe largest formula load in Class 11. Learn the identities in families, not as isolated lines.
Concepts you must be able to explain
- Radian measure: π radians = 180°, so 1 radian ≈ 57.3°. Arc length = rθ and sector area = ½r²θ with θ in radians.
- Signs of the six ratios follow the quadrant: ‘All, Sin, Tan, Cos’ in the first, second, third and fourth quadrants.
- Learn the sum and difference formulas first; the double-angle and triple-angle formulas are consequences of them.
- The product-to-sum and sum-to-product formulas are the standard route for converting expressions into a solvable form.
- General solutions: sin θ = sin α gives θ = nπ + (−1)ⁿα; cos θ = cos α gives θ = 2nπ ± α; tan θ = tan α gives θ = nπ + α.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Sum and difference | sin(A ± B) = sinA cosB ± cosA sinB; cos(A ± B) = cosA cosB ∓ sinA sinB | Watch the sign flip in cosine. |
| Double angle | sin2A = 2sinA cosA; cos2A = cos²A − sin²A = 1 − 2sin²A = 2cos²A − 1 | Three useful forms of cos2A. |
| Triple angle | sin3A = 3sinA − 4sin³A; cos3A = 4cos³A − 3cosA | Occasionally needed in proofs. |
| Sum to product | sinC + sinD = 2 sin((C+D)/2) cos((C−D)/2) | And the corresponding cosine and difference forms. |
| General solution | sinθ = sinα ⇒ θ = nπ + (−1)ⁿα | n ∈ ℤ for all three forms. |
| Arc and sector | arc = rθ; area = ½r²θ | θ must be in radians. |
Common mistakes
- Using degrees in formulas that require radians.
- Applying a double-angle formula when a single angle was asked for.
- Losing the ± in general solutions.
- Assuming sin²A + cos²A = 1 implies sinA + cosA = 1.
Exam tip: Write the formula sheet from memory once a day for a week. By the fifth day the identities start to feel obvious rather than arbitrary.
Complex Numbers and Quadratic Equations
Algebra · 25 marksA new number system with familiar algebra. Keep real and imaginary parts separate and most questions solve themselves.
Concepts you must be able to explain
- i = √(−1) and i² = −1. Powers of i repeat in a cycle of four: i, −1, −i, 1.
- A complex number z = a + ib has real part a and imaginary part b. Two complex numbers are equal only when both parts match.
- The conjugate of a + ib is a − ib. Multiplying by the conjugate removes i from a denominator.
- Modulus |z| = √(a² + b²) is the distance of z from the origin in the Argand plane.
- A quadratic with a negative discriminant has complex roots that occur in conjugate pairs.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Powers of i | i² = −1, i³ = −i, i⁴ = 1 | Reduce any power modulo 4. |
| Modulus | |z| = √(a² + b²) | Always non-negative. |
| Conjugate | z̄ = a − ib; z·z̄ = a² + b² | Used to rationalise denominators. |
| Division | (a + ib)/(c + id) = ((a + ib)(c − id))/(c² + d²) | Multiply by the conjugate of the denominator. |
| Quadratic roots | x = (−b ± √(b² − 4ac))/2a | If b² − 4ac < 0, write √(negative) as i√(positive). |
Common mistakes
- Writing √(−4) = −2 instead of 2i.
- Adding real parts to imaginary parts.
- Forgetting to multiply both numerator and denominator by the conjugate.
- Ignoring the conjugate pair when a real-coefficient quadratic has complex roots.
Exam tip: Convert every division into a multiplication by the conjugate before doing anything else. It is the only reliable way to get i out of the denominator.
Linear Inequalities
Algebra · 25 marksShort and graphical. The one rule that matters: multiplying or dividing by a negative number flips the inequality.
Concepts you must be able to explain
- Solve inequalities exactly like equations, except that multiplying or dividing by a negative number reverses the sign.
- The solution is a range of values, written in interval notation or shown on a number line.
- For two-variable inequalities, first draw the boundary line, then shade the half-plane that satisfies the inequality.
- A dashed boundary means strict inequality (< or >); a solid boundary includes the line (≤ or ≥).
- Systems of inequalities are solved by shading the region that satisfies every condition at once — the feasible region.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Interval notation | (a, b), [a, b], (a, ∞), (−∞, b] | Round bracket excludes the endpoint. |
| Sign flip | −2x > 6 ⇒ x < −3 | Dividing by a negative reverses the sign. |
| Half-plane test | Substitute (0, 0) into the inequality | If true, shade the side containing the origin. |
Common mistakes
- Forgetting to flip the inequality sign when dividing by a negative.
- Using a solid boundary for a strict inequality.
- Shading the wrong half-plane without a test point.
- Writing a solution set as a single number instead of a range.
Exam tip: Always test the origin (0, 0) unless the boundary passes through it. One substitution tells you which side to shade.
Permutations and Combinations
Algebra · 25 marksCounting with structure. Ask two questions every time: does order matter, and is repetition allowed?
Concepts you must be able to explain
- The fundamental principle of counting multiplies choices across independent stages.
- A permutation counts arrangements where order matters; a combination counts selections where order does not.
- nPr = n!/(n − r)! arranges r objects out of n; nCr = n!/(r!(n − r)!) selects them.
- nCr = nC(n − r), and nCr + nC(r − 1) = (n+1)Cr — both are frequently used to simplify expressions.
- Circular arrangements of n objects are (n − 1)!; if clockwise and anticlockwise are the same (as with garlands), divide by 2.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Factorial | n! = n(n − 1)(n − 2)…1, with 0! = 1 | Cancel factorials before multiplying. |
| Permutation | nPr = n!/(n − r)! | Order matters. |
| Combination | nCr = n!/(r!(n − r)!) | Order does not matter. |
| Symmetry | nCr = nC(n − r) | Choosing r is the same as rejecting n − r. |
| Pascal-type identity | nCr + nC(r − 1) = (n+1)Cr | Used when simplifying sums. |
| Circular arrangement | (n − 1)! | Divide by 2 if clockwise and anticlockwise are identical. |
Common mistakes
- Using permutations when the question asks for a committee or a selection.
- Forgetting to divide by the factorial of repeated letters in word arrangements.
- Cancelling factorials term by term — e.g. writing 5!/3! = 2!.
- Ignoring the ‘at least one’ condition and counting only the exact case.
Exam tip: Underline the words ‘arrange’ and ‘select’ in the question. They map directly to permutation and combination and settle most of the ambiguity.
Binomial Theorem
Algebra · 25 marksOne general term solves nearly every question. Find r, then everything else follows.
Concepts you must be able to explain
- For a positive integer n, (a + b)ⁿ = Σ nCr a^(n−r) b^r, with r running from 0 to n.
- The general term is T(r+1) = nCr a^(n−r) b^r. Equate powers to find the term that contains a given power.
- The number of terms in the expansion is n + 1.
- The middle term is the ((n/2) + 1)th term when n is even; there are two middle terms when n is odd.
- The binomial coefficients form Pascal’s triangle: each entry is the sum of the two above it.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Binomial expansion | (a + b)ⁿ = Σ(r=0 to n) nCr a^(n−r) b^r | Coefficients are nC0, nC1, …, nCn. |
| General term | T(r+1) = nCr a^(n−r) b^r | Set the exponent equal to the required power. |
| Middle term | n even ⇒ (n/2 + 1)th term | n odd ⇒ two middle terms. |
| Coefficient sum | nC0 + nC1 + … + nCn = 2ⁿ | Put a = b = 1 in the expansion. |
Common mistakes
- Confusing the term number with the value of r — T(r+1) is the (r + 1)th term.
- Forgetting to include the sign when the second term is negative.
- Treating the coefficient and the binomial coefficient as the same thing.
- Miscounting the middle term when n is even.
Exam tip: Write down T(r+1) and the required power of x, then solve for r. Do not expand the whole bracket — it wastes time and invites arithmetic errors.
Sequences and Series
Algebra · 25 marksAP and GP, plus the standard summation results. Recognise the pattern first, then pick the formula.
Concepts you must be able to explain
- An AP has a constant difference; a GP has a constant ratio. Check consecutive differences and ratios before assuming which one you have.
- For a GP, the nth term is ar^(n−1) and the sum of n terms is a(1 − rⁿ)/(1 − r) when r ≠ 1.
- An infinite GP converges only when |r| < 1, and then its sum is a/(1 − r).
- Arithmetic mean of a and b is (a + b)/2; geometric mean is √(ab). For positive numbers, AM ≥ GM.
- Standard sums: Σn = n(n + 1)/2, Σn² = n(n + 1)(2n + 1)/6, Σn³ = [n(n + 1)/2]².
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| AP nth term and sum | aₙ = a + (n − 1)d; Sₙ = n/2[2a + (n − 1)d] | Same as Class 10. |
| GP nth term | aₙ = ar^(n−1) | r is the common ratio. |
| GP sum | Sₙ = a(1 − rⁿ)/(1 − r), r ≠ 1 | Sum to infinity a/(1 − r) when |r| < 1. |
| Means | AM = (a + b)/2; GM = √(ab) | AM ≥ GM for positive a, b. |
| Standard sums | Σn = n(n+1)/2; Σn² = n(n+1)(2n+1)/6; Σn³ = [n(n+1)/2]² | Useful for series of the form n², n³. |
Common mistakes
- Using the AP formula for a GP or the reverse.
- Using the infinite-sum formula when |r| ≥ 1.
- Forgetting that the GP sum formula has two cases, r = 1 and r ≠ 1.
- Applying Σn² to an expression that is not a sum of squares.
Exam tip: Before solving, write the first three terms and compute both the difference and the ratio. The pattern tells you which set of formulas to use.
Straight Lines
Coordinate Geometry · 12 marksSlope, forms of a line and distances. Most answers become simple once you know the slope.
Concepts you must be able to explain
- Slope m = (y₂ − y₁)/(x₂ − x₁) measures steepness; a vertical line has undefined slope and a horizontal line has slope 0.
- Parallel lines have equal slopes; perpendicular lines have slopes whose product is −1.
- A line can be written in point-slope, two-point, slope-intercept or intercept form. Choose the form that matches the data given.
- The general equation ax + by + c = 0 has slope −a/b, x-intercept −c/a and y-intercept −c/b.
- The distance of a point from a line is |ax₀ + by₀ + c|/√(a² + b²).
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Slope | m = (y₂ − y₁)/(x₂ − x₁) | Undefined for a vertical line. |
| Point-slope form | y − y₁ = m(x − x₁) | When a point and the slope are known. |
| Two-point form | y − y₁ = ((y₂ − y₁)/(x₂ − x₁))(x − x₁) | Directly from two points. |
| Slope-intercept | y = mx + c | c is the y-intercept. |
| Distance from a line | |ax₀ + by₀ + c|/√(a² + b²) | Straight-line distance, not horizontal distance. |
| Perpendicular condition | m₁m₂ = −1 | Parallel: m₁ = m₂. |
Common mistakes
- Writing the slope as (x₂ − x₁)/(y₂ − y₁).
- Using the perpendicular condition for parallel lines.
- Forgetting the absolute value in the distance formula.
- Ignoring the undefined-slope case in problems involving vertical lines.
Exam tip: Find the slope first, then substitute into point-slope form. It is faster and less error-prone than juggling the general equation.
Conic Sections
Coordinate Geometry · 12 marksFour curves, a small set of standard forms and three things to find for each: focus, directrix and eccentricity.
Concepts you must be able to explain
- A circle is the set of points at a fixed distance from a centre. The standard form is (x − h)² + (y − k)² = r².
- A parabola is the set of points equidistant from the focus and the directrix. y² = 4ax opens right, x² = 4ay opens up.
- An ellipse satisfies the sum of distances to two foci being constant; a hyperbola satisfies the absolute difference.
- Eccentricity e = c/a compares the distance from the centre to a focus with the semi-major axis.
- For an ellipse, b² = a²(1 − e²); for a hyperbola, b² = a²(e² − 1).
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Circle | (x − h)² + (y − k)² = r² | Centre (h, k), radius r. |
| Parabola | y² = 4ax; focus (a, 0); directrix x = −a; latus rectum 4a | x² = 4ay opens upward instead. |
| Ellipse | x²/a² + y²/b² = 1, a > b; c² = a² − b²; e = c/a; latus rectum 2b²/a | Foci (±c, 0). |
| Hyperbola | x²/a² − y²/b² = 1; c² = a² + b²; e = c/a; latus rectum 2b²/a | e > 1; foci (±c, 0). |
| Eccentricity bounds | Ellipse: 0 < e < 1; hyperbola: e > 1; parabola: e = 1 | A quick check on your answer. |
Common mistakes
- Using c² = a² − b² for a hyperbola instead of c² = a² + b².
- Swapping the major and minor axes in an ellipse.
- Writing the wrong directrix for a parabola (x = −a, not x = a).
- Forgetting to complete the square before reading off the centre or vertex.
Exam tip: Write the standard form, then label a, b, c, e, focus and directrix on a sketch. Almost every conic question is a variation of that diagram.
Introduction to Three Dimensional Geometry
Coordinate Geometry · 12 marksCoordinates in space. The formulas look familiar because they are the two-dimensional ones with a z added.
Concepts you must be able to explain
- A point in space is written (x, y, z); the three axes are mutually perpendicular and divide space into eight octants.
- The distance formula adds a third squared difference under the root.
- The section formula and midpoint formula work exactly as in two dimensions, with the z-coordinate included.
- The centroid of a triangle with vertices (x₁, y₁, z₁), (x₂, y₂, z₂) and (x₃, y₃, z₃) is the average of the three points.
- Points on the coordinate axes have two zero coordinates; points in a coordinate plane have one zero coordinate.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Distance | √((x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²) | Three squared differences. |
| Section | ((m₁x₂ + m₂x₁)/(m₁ + m₂), same for y and z) | Ratio m₁ : m₂. |
| Midpoint | ((x₁ + x₂)/2, (y₁ + y₂)/2, (z₁ + z₂)/2) | Special case of 1 : 1. |
| Centroid | ((x₁ + x₂ + x₃)/3, same for y and z) | Average of the vertices. |
Common mistakes
- Forgetting the z-term in the distance formula.
- Mixing the coordinates of the two points halfway through the calculation.
- Assuming a point on the x-axis can have a non-zero y-coordinate.
- Using the two-dimensional section formula and dropping z.
Exam tip: Write the coordinates in the same order for both points and substitute mechanically. Most errors here are copying errors, not conceptual ones.
Limits and Derivatives
Calculus · 8 marksYour first formal look at calculus. Understand the limit idea and learn the standard derivatives cold.
Concepts you must be able to explain
- The limit of f(x) as x → a describes the value the function approaches, regardless of the value at a.
- A limit exists only when the left-hand and right-hand limits agree.
- Algebraic techniques for indeterminate forms: factorise and cancel, rationalise, or use standard limits.
- The derivative is the limit of the difference quotient: f′(x) = lim(h→0) [f(x + h) − f(x)]/h.
- Learn the derivatives of standard functions and the product, quotient and chain rules; the first-principles derivation is usually a 5-mark question.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Standard limit | lim(x→a) (xⁿ − aⁿ)/(x − a) = n·a^(n−1) | Very common in exams. |
| Trigonometric limits | lim(x→0) sin x / x = 1; lim(x→0) (1 − cos x)/x² = ½ | Angles in radians. |
| Derivative definition | f′(x) = lim(h→0) (f(x + h) − f(x))/h | First principles. |
| Derivatives | d/dx(xⁿ) = nx^(n−1); d/dx(sin x) = cos x; d/dx(cos x) = −sin x; d/dx(tan x) = sec²x | Memorise the table. |
| Rules | Product: (uv)′ = u′v + uv′; Quotient: (u/v)′ = (u′v − uv′)/v² | Chain rule for composite functions. |
Common mistakes
- Substituting x = a directly into an indeterminate form such as 0/0.
- Mixing degrees and radians in trigonometric limits.
- Using the quotient rule in the wrong order.
- Forgetting the negative sign in the derivative of cos x.
Exam tip: For first-principles questions, write the definition, expand f(x + h), cancel h, then take the limit. The method marks are for those four steps.
Statistics
Statistics and Probability · 12 marksDispersion rather than averages. The calculations are long, so organisation is everything.
Concepts you must be able to explain
- Mean deviation is the average of the absolute deviations from a central value — either the mean or the median.
- Variance is the average of the squared deviations from the mean; standard deviation is its positive square root.
- For grouped data, use the class marks and the frequency-weighted formulas.
- The coefficient of variation is standard deviation divided by the mean, often expressed as a percentage; it compares variability between data sets.
- A short-cut method using assumed mean and step deviation reduces arithmetic for grouped data.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Mean deviation | MD = (Σ|xᵢ − x̄|)/n | Or from the median. |
| Variance | σ² = (Σ(xᵢ − x̄)²)/n = (Σxᵢ²)/n − x̄² | The second form is easier for decimals. |
| Standard deviation | σ = √variance | Same units as the data. |
| Coefficient of variation | CV = (σ/x̄) × 100% | Used to compare consistency. |
| Grouped variance | σ² = (Σfᵢxᵢ²)/N − (Σfᵢxᵢ/N)² | N = Σfᵢ. |
Common mistakes
- Forgetting to square deviations before averaging for variance.
- Mixing up Σf with N when computing grouped statistics.
- Taking the standard deviation of the class limits instead of the class marks.
- Reporting variance in the original units — only standard deviation has the original units.
Exam tip: Make a table with columns for x, f, fx, x², fx² from the start. It prevents almost every arithmetic error in this chapter.
Probability
Statistics and Probability · 12 marksSet-based probability. Draw the sample space, then use the addition rule carefully.
Concepts you must be able to explain
- A random experiment has a sample space of all possible outcomes; an event is a subset of that sample space.
- For equally likely outcomes, P(A) = number of outcomes in A / total number of outcomes.
- The addition rule P(A ∪ B) = P(A) + P(B) − P(A ∩ B) corrects for double counting.
- Mutually exclusive events have P(A ∩ B) = 0; independent events satisfy P(A ∩ B) = P(A)P(B).
- The complement rule P(A′) = 1 − P(A) simplifies many ‘at least one’ questions.
Formulas and rules
| Name | Formula / rule | When to use it |
|---|---|---|
| Probability | P(A) = n(A)/n(S) | S is the sample space. |
| Addition rule | P(A ∪ B) = P(A) + P(B) − P(A ∩ B) | For any two events. |
| Complement | P(A′) = 1 − P(A) | Useful for ‘at least one’. |
| Mutually exclusive | P(A ∩ B) = 0 | Then P(A ∪ B) = P(A) + P(B). |
| Independent | P(A ∩ B) = P(A)P(B) | Not the same as mutually exclusive. |
Common mistakes
- Adding probabilities without subtracting the overlap.
- Confusing independent events with mutually exclusive events.
- Forgetting that probabilities must lie between 0 and 1.
- Assuming outcomes are equally likely when they are not (for example, loaded dice).
Exam tip: Draw a Venn diagram or write out the sample space. The addition rule becomes obvious once you can see which outcomes are counted twice.
A revision routine that actually works
Read the chapter once, slowly
Do not highlight. Read to understand the one idea the chapter is built on, then close the book and say it aloud in your own words.
Rebuild the formula table from memory
Write the formulas on a blank sheet. Compare with the table above. Every formula you miss goes on a separate “mistakes” page you review weekly.
Solve 5 NCERT questions before any reference book
NCERT exercises are the closest thing to the board paper. Finish the exercise before opening a question bank.
Do one previous-year question under a timer
Time pressure is a separate skill. Ten minutes of timed practice beats an hour of untimed reading.
Teach the chapter to someone
Explaining a theorem to a friend exposes gaps that rereading never will. If nobody is around, explain it to a wall — seriously.
What to read next
Quick answers students search for
How many chapters are there in Class 11 maths?
The rationalised CBSE Class 11 Mathematics syllabus for 2026-27 has 14 chapters in five units. Mathematical Reasoning and the Principle of Mathematical Induction are no longer part of the summative exam.
Is there chapter-wise weightage in Class 11?
CBSE explicitly states that there is no chapter-wise weightage. Unit-wise marks are published (Sets and Functions 23, Algebra 25, Coordinate Geometry 12, Calculus 8, Statistics and Probability 12), so every chapter needs cover.
Does Ritik Sir teach Class 11?
His Physics Wallah batches focus on CBSE Classes 9 and 10. These Class 11 notes are an independent study resource for students moving into senior secondary maths.
Last updated: 22 October 2026 · Author: Bazid Ahmed Laskar · This page is independent study material and is not affiliated with Physics Wallah or Ritik Mishra.